Solve the inequality in terms of intervals and illustrate the solution set on the real number line. $ 4 - 3x \ge 6 $
nroka asked a year ago
here,
4−3x≥64 - 3x \ge 64−3x≥6
so, −2≥3x-2 \ge 3x−2≥3x
so, x≤−23x \le -\frac{2}{3}x≤−32
The value of xxx is less than or equal to -2/3.
so the interval is (−∞,−23]( -\infin, -\frac 23 ](−∞,−32]
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here,
so,−2≥3x
so,x≤−32
The value ofx is less than or equal to -2/3.
so the interval is(−∞,−32]
davidmacago answered a year ago