Differentiate the following function. f(t) = 4 7 t7 + 1

To solve the question f(t) = 4/7(t^7 + 1), we can write it as, y = 4/7(t^7 + 1),

take derivative on both sides with respect to t because we have t variable in the question,

$\frac{dy}{dt}$ = $\frac{d(\frac 47 t^7)}{dt}$ + $\frac{d(\frac 47)}{dt}$

• If there is constant (4/7) with variable (t^7), we plug out the constant and take the derivative of variable.
• If there is only constant, we take its derivative. The derivative of constant is zero.

= $\frac 47 \times 7t^6$ + 0

= 4t⁶