how to differentiate it i'm stuck.
y = 8ex+4x38e^x + \frac{4}{\sqrt[3] x}8ex+3x4
davidmacago asked 2 years ago
take derivative on both sides with respect to x,
dydx\frac{dy}{dx}dxdy = 8dexdx8\frac{de^x}{dx}8dxdex + exd8dxe^x \frac{d8}{dx}exdxd8 + 4x−13dx4\frac{x^{-\frac 13}}{dx}4dxx−31
= 8ex8e^x8ex + 0 - 43x−43\frac 43{x^{\frac {-4}{3}}}34x3−4
= 8ex8e^x8ex - 43x43\frac{4}{3x^{\frac 43}}3x344
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take derivative on both sides with respect to x,
=8ex + 0 - 34x3−4
=8ex - 3x344