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Differentiate the function. y = 8e^x + 4/ 3sqrt x

how to differentiate it i'm stuck.

y = 8ex+4x38e^x + \frac{4}{\sqrt[3] x}

davidmacagodavidmacago asked 2 years ago

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Answers

1

take derivative on both sides with respect to x,

dydx\frac{dy}{dx} = 8dexdx8\frac{de^x}{dx} + exd8dxe^x \frac{d8}{dx} + 4x13dx4\frac{x^{-\frac 13}}{dx}

= 8ex8e^x + 0 - 43x43\frac 43{x^{\frac {-4}{3}}}

= 8ex8e^x - 43x43\frac{4}{3x^{\frac 43}}

  • Derivative exe^x is exe^x.
  • Derivative of constant is 0.
  • Derivative of xnx^n is nxn1nx^{n-1}

davidapdavidap answered 2 years ago

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