Logo
0

Evaluate the lim x-> infinity (-3x^4 - x^2 + 5)/(2x^5 - 7x^3)

Hello there. x approaches ∞ is stopping me to move my pen. Help me, please. How can I solve it?

davidapdavidap asked 2 years ago

·

Answers

1

Hey, Dibas. Don't worry buddy!

The process for doing this type of question where x approaches infinity is totally different than other questions where x approaches any real numbers like this question.

In this type of question, we should look at the values of the denominator which has the highest power of x or any variable depending on the questions. And then divide by that value which has the highest power in both the numerator and denominator.

After that, we just need to substitute the ∞ or -∞ in the expression and get our result.

= limx3x4x2+52x57x3lim_{x \, \to \, \infin} \frac{-3x^4 \, - \, x^2 \, + \, 5}{2x^5 \, - \, 7x^3}

= limx3x4x5x2x5+5x52x5x57x3x5lim_{x \, \to \, \infin} \frac{\frac{-3x^4}{x^5} \, - \, \frac{x^2}{x^5} \, + \, \frac{5}{x^5}}{\frac{2x^5}{x^5} \, - \, \frac{7x^3}{x^5}}

= limx3x1x3+5x527x2lim_{x \, \to \, \infin} \frac{\frac{-3}{x} \, - \, \frac{1}{x^3} \, + \, \frac{5}{x^5}}{2 \, - \, \frac{7}{x^2}}

= 00+020\frac{-0-0+0}{2-0}

= 0

davidmacagodavidmacago answered 2 years ago

Post your answer

Recommended Books

Reading books is a great way to learn. Here are some of the books we recommend.