Find the derivative of the function. y = 3 cot 5????

To solve this question, u need to know about the chain rule and the formula for the derivative of cot???? which is -csc²????.

so, y = 3 cot 5????

or, $\frac{dy}{d\theta}$ = $\frac{3cot5\theta}{d\theta}$ = $3 \times \frac{cot5\theta}{d(5\theta)} \times \frac{d(5\theta)}{d\theta}$ = -3csc²5θ × 5 = -15csc²5θ